Math Problem: Irrational Inequation

GamerzHell9137

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What am i doing wrong?

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sabykos

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I just took a brief look. You're not allowed to take the square of inequations. For example:

-1 > -2 is true, but (-1)²=1>4=(-2)² obviously not.
 

GamerzHell9137

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@sabykos
I know that there's one rule that says that w/e its on square must be > or >= than it, maybe i was supposed to put >=
But other than that, is the way i did the inequation wrong?
 

Deboog

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@sabykos That isn't an issue because one of the numbers is 4 and the other number is greater than 4. So both numbers are positive, squaring them will keep the inequality in the same direction.
@GamerzHell9137 You people in Bosnia have a very strange way of writing powers. =P I thought that it was 21 squared at first.
 

Deboog

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Alright. So after looking at it more, I realized that Sabykos is actually right. When square both sides the FIRST time it is fine because you can prove that both sides are positive. When you square both sides the SECOND time it is not fine because you cannot prove that both sides are positive. In fact, the right side can very well be negative. A workaround is to, as a first step multiply both sides by root(4-3x) + root(x+1) which will move the root mess over to the right side. Then, after you square both sides and simplify you will get 16x^2 - 4x -11 > 8root[(4-3x)(x+1)] Thankfully, we can prove both sides are positive, the short version is square roots are positive, and so a square root times 8 is positive, and the left is greater than a positive so it's also positive.
 

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