- Joined
- Feb 26, 2017
- Messages
- 4,046
- Trophies
- 2
- Age
- 20
- Location
- Hollister, CA
- Website
- dionicio3.com
- XP
- 7,253
- Country
There has been an issue troubling our social for eons. That issue is, "what is Kingy's sexuality." Well, after countless hours of studying the man, I have finally found the answer.
As everyone knows, exponents are used to multiply the same thing over and over again (2² = 2×2, 2³ = 2×2×2, etc.). Also something everyone should know, is that 0ⁿ will always be 0 (Excluding 0 itself). It doesn't matter what number you use 0², 0³, 0⁴, or even 0²¹³⁴²³.
We can use the formula Kingy - Kin + a = gay. But what does "gay" actually mean? Well, before I answer that, I bet you're wondering, "Can Kingy = Straight using Kingy - Kny + Straht?" Well no, because the true answer to that would be Kingy = St²raigh, and using exponents is gay (I'll explain this more later on). Using the gay formula of @SimonMKWii (proof here), we know that gay = 0. Remember how we talked about 0 in the first part? Well, exponents being gay and 0 all come together in a new mathematic principal I'm naming "Skiddo's Principal." The principal explains gay, since gays try to multiply with each, they're basically an exponent. However, since the gay formula says gay = 0, the outcome will always be 0. As Kingy = gay, gay = 0, so Kingy = 0. We can then assume that the t in Kingy = St²raigh is equal to 0, which means St²raigh = gay, so, Kingy once again equals gay.
Using these new found formulas, I created a deviced called "the bisexual detector," since it could only be used by people with at least 50% gayness. This machine detects the gayness radiating out of any individual over 25% gay. As I test, I used it on myself, and sure enough, it said 50% gay. So I then pointed it at Kingy, and the results astounded me. 75% gayness, within the threshold of being gay. Thanks to all this hard work, we can once and for all, finally say that Kingy is indeed gay.
I would like to thank @Kingy_ for letting me research on him, as well as @SimonMKWii for creating the wonderful formula, as well as letting me use a screenshot of the proof. And last but not least, I want to thank everyone who helped crack this mystery.
1. Some basics of maths
As everyone knows, exponents are used to multiply the same thing over and over again (2² = 2×2, 2³ = 2×2×2, etc.). Also something everyone should know, is that 0ⁿ will always be 0 (Excluding 0 itself). It doesn't matter what number you use 0², 0³, 0⁴, or even 0²¹³⁴²³.
2. The basic formulas to hypothesize this
We can use the formula Kingy - Kin + a = gay. But what does "gay" actually mean? Well, before I answer that, I bet you're wondering, "Can Kingy = Straight using Kingy - Kny + Straht?" Well no, because the true answer to that would be Kingy = St²raigh, and using exponents is gay (I'll explain this more later on). Using the gay formula of @SimonMKWii (proof here), we know that gay = 0. Remember how we talked about 0 in the first part? Well, exponents being gay and 0 all come together in a new mathematic principal I'm naming "Skiddo's Principal." The principal explains gay, since gays try to multiply with each, they're basically an exponent. However, since the gay formula says gay = 0, the outcome will always be 0. As Kingy = gay, gay = 0, so Kingy = 0. We can then assume that the t in Kingy = St²raigh is equal to 0, which means St²raigh = gay, so, Kingy once again equals gay.
3. My new invention to prove this.
Using these new found formulas, I created a deviced called "the bisexual detector," since it could only be used by people with at least 50% gayness. This machine detects the gayness radiating out of any individual over 25% gay. As I test, I used it on myself, and sure enough, it said 50% gay. So I then pointed it at Kingy, and the results astounded me. 75% gayness, within the threshold of being gay. Thanks to all this hard work, we can once and for all, finally say that Kingy is indeed gay.
4. Credits
I would like to thank @Kingy_ for letting me research on him, as well as @SimonMKWii for creating the wonderful formula, as well as letting me use a screenshot of the proof. And last but not least, I want to thank everyone who helped crack this mystery.
